LEARN · 2026-10-07
How to calculate gear ratio: single-stage, compound and planetary gear ratio formulas (with torque and speed)
Gear ratio = driven teeth ÷ driver teeth. Learn how single and compound gear trains set output speed and torque, typical efficiencies of each drive, and where the planetary ratio 1 + Zr/Zs and its assembly conditions come from — with a worked design example.
What is a gear ratio?
The ratio i is input speed divided by output speed. Meshing gears share the same pitch-line velocity, so speed is inversely proportional to tooth count: one turn of the pinion turns the wheel z₁ / z₂ of a turn.
i = z₂ / z₁ = n₁ / n₂ = d₂ / d₁
A 15-tooth pinion driving a 45-tooth gear gives i = 3: a 3000 rpm motor becomes 1000 rpm. i > 1 reduces speed, i < 1 increases it. Two external gears turn in opposite directions; an idler reverses rotation again without changing the ratio.
TIPRatios are written 3:1, 1:3 or simply "ratio 3" depending on the industry. Always confirm which side is the input before comparing specs.
Speed, torque and power
n₂ = n₁ / i T₂ = T₁ · i · η P (kW) = T (N·m) × n (rpm) / 9549
Gears don't create energy: speed falls by i, torque rises by i, and efficiency η takes its share. A 0.5 N·m motor at 3000 rpm delivers about 157 W; through an i = 9 gearbox at 96% it gives 333 rpm and 4.32 N·m — still about 151 W.
| Drive | Typical ratio per stage | Efficiency |
|---|---|---|
| Spur / helical (steel, lubricated) | 1–6(≤ 8) | 97–99% |
| 3D-printed plastic gears | 1–5 | 90–95% |
| Bevel gears | 1–5 | 95–98% |
| Planetary (ring fixed) | 3–10 | 95–98% |
| Worm drive | 5–100 | 30–90% |
| Timing belt | 1–6 | 95–98% |
| Roller chain | 1–7 | 95–98% |
These are ballpark figures. Ground steel gears reach 99%; printed PLA or PETG gears with rough flanks and backlash manage about 90–95% per stage; worm drives depend heavily on lead angle and lubrication.
Compound gear trains: multiply the stages
i total = (z₂/z₁) × (z₄/z₃) × (z₆/z₅) … η total = η₁ × η₂ × η₃ …
In a compound train the first-stage gear and second-stage pinion share a shaft. With 15→45 and 12→36: i = 3 × 3 = 9 and, at 98% per stage, total efficiency 0.98² ≈ 96%. Doing 9:1 in one stage would need a 135-tooth gear for a 15-tooth pinion.
- Keep each stage at ≤ 6–8; beyond that add stages or use a planetary or worm drive.
- Start each stage at the n-th root of the total ratio: i = 20 in two stages ≈ 4.47 × 4.47, in practice 4 × 5 (15→60, 15→75).
- A 20° pinion with fewer than 17 teeth undercuts; positive profile shift helps. For 3D printing stay at ≥ 12 teeth with shift.
- Backlash accumulates and is multiplied by the downstream ratios, so positioning gearboxes should use as few stages as possible.
TIPPick co-prime tooth counts (15:46 rather than 15:45) so every tooth meets every other tooth in turn. This "hunting tooth" ratio evens out wear — especially useful for printed gears.
Planetary gear ratio: why 1 + Zr/Zs?
A planetary set has a sun (Zs), several planets (Zp), a ring gear (Zr) and a carrier. The usual layout fixes the ring, drives the sun and takes output from the carrier. Because the carrier itself rotates, the ratio is not simply Zr/Zs — it follows from the Willis equation:
(ns − nc) / (nr − nc) = −Zr / Zs → ring fixed (nr = 0): i = ns / nc = 1 + Zr / Zs
| Fixed | Input | Output | Ratio | Direction |
|---|---|---|---|---|
| Ring | Sun | Carrier | 1 + Zr/Zs | Same |
| Sun | Ring | Carrier | 1 + Zs/Zr | Same |
| Carrier | Sun | Ring | Zr/Zs | Reversed |
Assembly: Zr = Zs + 2·Zp (Zs + Zr) / N = integer (N = number of planets)
Zs = 12, Zp = 24, Zr = 60 gives i = 1 + 60/12 = 6 and (12 + 60)/3 = 24, so three planets fit. Zs = Zp = 20, Zr = 60 gives i = 4 with four planets ((20 + 60)/4 = 20) but not three. Neighbouring planets must also clear each other: planet tip diameter < 2a·sin(180°/N), where a is the sun–planet centre distance.
TIPThe internal gear generator's "Planetary m1 · 60T" preset matches these tooth counts. Printed planetary gearboxes often use herringbone teeth, which self-centre and can't slide out axially.
Worked example: from requirement to tooth counts
- Input: NEMA 17 stepper giving about 0.4 N·m at 600 rpm.
- Requirement: 100 rpm and at least 2 N·m, so i = 600 / 100 = 6.
- Torque check: T₂ = 0.4 × 6 × 0.95 ≈ 2.28 N·m — enough (apply a 1.5–2 safety factor for critical use).
- Layout: one planetary stage Zs 12 / Zp 24 / Zr 60 gives exactly i = 6 on a coaxial output, or two spur stages 15→37 and 15→36 (i ≈ 5.92).
- Centre distance: spur a = m(z₁ + z₂)/2 = 26 mm for m1, 15→37; sun–planet a = 1 × (12 + 24)/2 = 18 mm.
- Check efficiency, speed and direction in the gear ratio calculator, then download the gears from the generators.
FAQ
What does a 1:10 ratio mean?
The input turns 10 times for one output turn. Output speed is 1/10 of the input and torque is about 10× higher, minus efficiency losses.
Does an idler gear change the ratio?
No. Its tooth count cancels out of the formula; it only reverses direction and adds distance between shafts.
Does a higher ratio increase motor power?
No. Power = torque × speed; a reduction trades speed for torque, and losses make output power slightly lower.
Why isn't the planetary ratio just Zr/Zs?
With the ring fixed, the carrier rotates too. The sun turns Zr/Zs times relative to the carrier, plus one turn of the carrier itself, so i = 1 + Zr/Zs. Only with the carrier fixed is the ratio Zr/Zs — and reversed.
How do I calculate pulley or sprocket ratios?
The same way: driven teeth ÷ driver teeth. A GT2 20-tooth pulley driving a 60-tooth pulley is i = 3; for flat or V-belts divide pitch diameters.